Solution:
Let X be the relative abundance of the isotope with relative mass 63.0. Then the relative abundance of the 65.0 isotope is (1-X). Thus:
"63.0\\times{X}+65.0\\times(1-X)=63.5"
"65.0-2\\times{X}=63.5"
"X=0.75"
The relative abundance of the isotope with mass 63.0 is "0.75=75\\%" . Therefore, the relative abundance of the 65.0 isotope is "(1-0.75)=0.25=25\\%" .
Answer:
The relative abundance of the isotope with mass 63.0 is "0.75=75\\%" . Therefore, the relative abundance of the 65.0 isotope is "0.25=25\\%" .
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