Given the molar concentration of Melanoic acid = 1.935 M
Melanoic acid is a di-basi acid
So, normal concentration of Melanoic acid
C = (1.935 × 2) N
Or, C = 3.87 N
Melanoic acid is a weak acid,
We know pH of a weak acid,
pH = 0.5 ( –log Ka – log C )
Or, pH = 0.5 [ – log (2.3 × 10^-4) – log 3.87 ]
Or, pH = 0.5 [ 3.638–0.587 ]
Or, pH = 1.52
Hence, pH of 1.935 M aqueous solution of Melanoic acid = 1.52
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