We know that dihydrogen (H2) has 2 hydrogen atoms per molecule, so there will be 2 * 1g hydrogen per mole = 2g dihydrogen per mole. If there are 2g dyhydrogen per mole, and we have 4g, then we know 4g / 2g per mole = 2 mole dihydrogen in 4g. So n1=2mole
So asusal 33g Co2=33/44 mole Co2
=0.75mole
So,n2=0.75mole
Volume of hydrogen gas(V1)=20L
Volume of Co2(V2)=?
So from ideal gas equestion we can write
P1V1/n1T1=P2V2/n2T2
Here,the temperature and pressure are constant.so we can write this equation
20L/2mole=V2/0.75mole
V2=0.75mole*20L/2
V2=7.5L
Hence the volume of CO2 is 7.5L
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