Answer to Question #138638 in General Chemistry for Lily Malaeb

Question

a 25ml sample of dilute h2so4 is titrated with 0.0965m naoh so that both protons of h2so4 are neutralized it takes 17.83ml of base to reach end point what is the molarity of h2so4

Answer 1

Given,

Volume of H₂SO_4, (V1) = 25ml

Strength of NaOH = 0.0965 m

For the titration purpose Normal strength of NaOH will used

So,

Normally of the NaOH = (0.0965×no. of OH^– in 1 molicule of NaOH)

=( 0.0965×1 ) N

= 0.0965 N

Normally of the NaOH, S₂ =0.0965 N

Volume of NaOH takes,V₂ = 17.83ml

Let, the normal strength of H₂SO₄ = S₁ N

For Acid base neutralization reaction,

V₁S_{1 =} V₂S₂

Or, S₁ = (V₂S₂/V₁)

= ( 0.0965 N ×17.83 ml )/25 ml

= 0.0688 N

For H₂SO₄

Normal strength= ( molarity × no. of proton in it )

Or, Normal strength= ( molarity × 2 )

Or, molarity = (normal strength/2)

Or, molarity =( 0.0688/2 ) M

= 0.0344 M

Hence, molarity of H₂SO₄ = 0.0344 M