2)at stp volume of a given mass of gas is 22.4L when pressure is 760mmHg and temperature 273k
Since, P1V1/T1 = P2V2/T2 and; P1= 760mmHg, V1=22.4L, T1= 273K , P2= 946mmHg, V2 = n T2 =284K
To get n (V2) = 760.ommHg*22.4L/273.0K= 946.0mmHg*n/284K
n =760*22.4*284/273*946
n= 18.7L
Therefore the volume of the sample of neon is 18.7L
3)Given that 28.8g of Na reacts with water at r.t.p( pressure 1atm and temperature 25°C)
Equation: 2Na(s) + 2H2O(l) = 2NaOH(aq) + H2(l)
moles of Na = 28.8g/23.0g/m = 1.252 moles
Mole ration of Na to H2 = 2:1
Moles of H2 = 1*1.252/2= 0.621 moles
if volume of 1mol of H2 at r.t.p is 24.0L;
0.621moles = 24.0L*0.621moles/1 mol= 15.026L
Volume of H2 is therefore 15.026L
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