Answer to Question #138535 in General Chemistry for mena

Question

A sample of gas at 25.0oC has a volume of 3.20L at a pressure of 100kPa. What would its volume be if the pressure was increased to 1.3atm and the temperature was decreased to -57.0oC?

Answer 1

According to the equation,

P₁V₁/T₁ = P₂V₂/T₂

P₁ = 100kpa = 0.98 atm

V₁ = 3.20 L

T₁ = 25 0C = 298K

P₂ = 1.3 atm

T₂ = -57 OC = 216K

V₂ = ?

V₂ = (0.98 x 3.20 x 216)/(298 x 1.3) = 1.748 L (Ans.)