Given the density of the solution = 1.1 gram/ ml
So the mass of 150 ml of aqua solution = 150 x density of the solution
 = 150 ml X 1.1 gram /ml
=165 grams
According to the given data,
Magnesium chloride present in the solution = 20% by mass of the solution
 =( Mass of solution×20)/100 gram
= 166×20/100 gram
 =33.2 grams
hence, mass of the magnesium chloride needed to prepare a solution of 20% of magnesium chloride by mass = 33.2 grams of magnesium chloride
Comments
Leave a comment