Answer to Question #138475 in General Chemistry for Javier

Question

When 2.00 liters of SO3 gas at STP react, how many grams of O2 gas will form?
2SO3(g) → 2SO2(g) + O2(g)

Answer 1

n(SO3)= V/Vm      n(SO3)=2/22,2=0,09 mole
n(O2)=0,089/2=0,045 mole

$m=n*M$

m(O₂ )= 0,045*32=1,44 g.

answer: 1,44 g.