Answer to Question #138474 in General Chemistry for Javier

Question #138474

How many grams of Ca metal are needed to react with 15.3 liters of N2 gas at STP?
3 Ca(s) + N2(g) → Ca3N2(s)

Expert's answer

n (N₂) ="V\/V"m n (N2)=15,3/22,4=0,683 mol n(Ca)=3*0,683=2 mol

m( Ca)=n*M=2*40=80 g.

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