Question

A gas containing 0.42 mole of helium has a volume of 3.00 L. What is the new volume when 1.0 mole of nitrogen is added to the container (pressure and temperature remain constant)?

Answer 1

$$V_m = V/n = 3.00L/0.42mol = 7.14 L/mol$$

$$V_1 = 7.14 L/mol * 1 mol = 7.14 L$$