Answer to Question #138296 in General Chemistry for Joy Abraham

Question

24cm of 0.2M sodium hydroxide was used to tritrate against 20cm of sulphuric acid. What was the concentration of sulphuric acid (in M)

Answer 1

24cm of 0.2M sodium hydroxide was used to tritrate against 20cm of sulphuric acid.

So, V = 24cm, S = 0.2 M

& V' = 20cm , S' = ?

Hence, VS=V'S'

So,(24cm)(0.2M)=(20cm)(S')

S' = 0.24M

Hence, the concentration of sulphuric acid is 0.24M