Let x ml of 10.0 M NaOH have to added, with the 100 ml of 1.00 M NaOH solution.
So, V = x ml, S = 10.0 M
& V' = 100 ml , S' = 1.00 M
Total volume of solution = (100 +x)ml
Hence the resulting concentration of NaOH =[(VS+V'S')/total volume] M
=[(10x+200) /(100+x)] M
Given resulting concentration of NaOH = 5.00 M
So,
[(10x+200) /(100+x)] = 5
Or, 10x + 200 = 500 + 5x
Or, 5x = 300
Or, x = 60
Hence, 60 ml of 10.0 M NaOH need to add to get the solution of required strength.
Comments
is it typo? 200?
why +200
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