Solution:
K: 1s22s22p63s23p64s1 radius of the neutral atom = 0.231 nm
K+: 1s22s22p63s23p6 radius of the ion= 0.133 nm
Cl: 1s22s22p63s23p5 radius of the neutral atom = 0.099 nm
Cl- : 1s22s22p63s23p6 radius of the ion = 0.181 nm
Na: 1s22s22p63s1 radius of the neutral atom = 0.186 nm
And then, in order of increasing size are Cl, K+, Cl-, Na, K
Answer: in order of increasing size are Cl, K+, Cl-, Na, K
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