Question

A 60.0L tank of chlorine gas at 27°C and 125atm springs a leak. When the leak was discovered, the pressure was reduced to 50atm. How many moles of chlorine gas escaped?

Answer 1

Let's solve the Clapeyron-Mendeleev equation by equation:

$P1V=n1RT$

$P2V=n2RT$

$(P1-P2)V=(n1-n2)RT$

$\Delta PV=\Delta nRT$

$\Delta n=\frac{\Delta PV}{RT}$

$\Delta n=\frac{\Delta PV}{RT}=\frac{(125-50)60}{0.082*300}=\frac{4500}{24.6}=182.93$ mol