Question

Calculate each of the following quantities in 2.50 moles H3PO4:

atoms of O

Answer 1

Given,

the molicular formula = H3PO4

Hence, no. Of 'O' atom in each molicule of H3PO4 is = 4

1 mole = 6.023×10^23 molicules

2.50 mole =( 2.50× 6.023×10^23 )molicules

= 15.057 × 10^23 molicules

So,

In 1 molicule of H3PO4, 4 atom of O

In (15.057 × 10^23) molicules of H3PO4, ( 4×15.057 × 10^23) atoms of O

Hence,

in 2.50 moles of H3PO4 there are 60.228 × 10^23 atoms of O