Answer to Question #137315 in General Chemistry for Isurini Sirisena

Question

The overall equation for one method of manufacturing
hydrogen from methane is
CH4 + 2H2O → 4H2 + CO2
In one batch, 5.12 tonnes of hydrogen were obtained from
13.6 tonnes of methane.
What is the percentage yield of hydrogen for this batch?
A 37.6
B 42.5
C 54.4
D 75.3

Answer 1

m₁(H₂) = 5.12 tones

m(CH₄) = 13.6 tonnes = 13 600 000 g

n(CH₄) = m(CH₄)/M(CH₄) = 13 600 000/(12+1*4)= 850 000 mole

850 000 mole x mole

CH₄ + 2H₂O → 4H₂ + CO₂

1 mole 4 mole

850 000/1 = x/4

x = (850 000*4)/1 = 3 400 000 mole = n(H₂)

m₂(H₂) = n(H₂)*M(H₂) = 3 400 000 * (1+1) = 6 800 000 g = 6.8 tones

percentage yield of hydrogen = m₁(H₂)/m₂(H₂) * 100% = 5.12/6.8 * 100% = 75.3%

answer D 75.3