Answer to Question #136993 in General Chemistry for mica

Question

You have 235.5 g of Ba(OH)2.
Part 1
How many moles of barium hydroxide, Ba(OH)2, are present in 235.5 g?

mol Ba(OH)2
Part 2
How many moles of barium ions are present in Part 1?

mol Ba2+
Part 3
How many moles of hydroxide ions are present in Part 1?

mol OH1-

Answer 1

PART 1

Ba = 137.327g

O = 16g

H = 1.008g

Molar mass Ba(OH)₂ = (137.327+2(16)+2(1.008))g

Ba(OH)₂ = 171.34g

Therefore : 1 Mol = 171.343g

? = 235.5g

= (235.5/171.343) = 1.4Moles

PART 2

1 mol of Ba⁺ = 137.327

? = 171.343

=1.2moles

PART 3

1.4 moles = 2mol

? = 1 mol

(1.4/2) =0.7 moles