Given,
Volume of solution = 155 mL
Strength of the sulfuric acid (H2SO4) = 1.575 M
Strength of the acid solution = 1.575M means,
1000 mL of solution contain 1.575 mole of sulphuric acid molecule
So, 1 mL of solution contain = (1.575/1000) mole sulphuric acid molecule.
155 mL solution contain = (1.575/1000)×155 mole sulphuric acid molecule.
= 0.244 mole
(Up to 3 significant decimal place)
Chemical formula of sulphuric acid is = H2SO4
Assuming fully dissociation of H2SO4
1 mole of H2SO4 produces 2 moles of H+ iones
0.244 mole of H2SO4 produces (2×0.244) moles of H+ iones
= 0.488 mole of H+ ione
Hence,
number of moles of the H+ ion in 155 mL of 1.575 M sulfuric acid (H2SO4) assume the acid fully dissociates is = 0.488 mole
Comments
Leave a comment