Question #136687

While panning for gold you find a cube-shaped nugget that looks like gold. You find its mass to be 1.24 g. You know that the density of real gold is about 19.3 g/cm3 and that the density of fool's gold is 5.0 g/cm3. If the cubic nugget is about 0.40 cm on each side, determine if you have real gold or fool’s gold in your possession.

Expert's answer

Volume of the nugget = l x w x h

= (0.4 x 0.4 x 0.4)cm3

= 0.064cm3


Density of the nugget =massvolume=\dfrac{mass}{volume}


=1.24g0.064cm3= \dfrac{1.24g}{0.064cm^3}


= 19.375g/cm3


Conclusion: The nugget contains pure gold

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