Question

how many grams of sulfur are in 5.53g sample of al2(so3)3

Answer 1

Molar mass of $Al_2(SO_3)_3=294 \ g.$

So , $294\ g$ of $Al_2(SO_3)_3$ Contain $96\ g$ of sulfur

$1\ g$ of $Al_2(SO_3)_3$ will have $\frac{96}{294}\ g$ of sulfur.

$5.53\ g$ of $Al_2(SO_3)_3$ will have $\frac{96}{294}\times 5.53= 1.80\ g$ of sulfur