Answer to Question #136218 in General Chemistry for Jmowns

Question

What volume of of 0.25 M H2SO4 is needed to react with 40.0 ml of 0.25 M Barium hydroxide?

Answer 1

H₂SO₄+Ba(OH)₂=BaSO₄+H₂O

$C1\times V1=C2\times V2$

$V2=\frac{C2\times V2}{C1}=\frac{0.04\times0.25}{0.25}=0.04 L$