Solution.
x = n(NaCl)
y = n(KCl)
M(NaCl) = 58.44 g/mol
M(KCl) = 74.55 g/mol
"n(AgNO3) = C \\times V = 0.012 mol"
"58.44 \\times x + 74.55 \\times y = 0.770"
"x + y = 0.012"
x = 0.0077 mol
y = 0.0043 mol
m(NaCl) = 0.45 g
m(KCl) = 0.32 g
"w(NaCl) = \\frac{0.45}{0.77} \\times 100 \\% = 58.44 \\%"
"w(KCl) = \\frac{0.32}{0.77} \\times 100 \\% =41.56 \\%"
Answer:
w(NaCl) = 58.44 %
w(KCl) = 41.56 %
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