QUESTION # 135355
The pressure of gas is recorded as 1.0 x 105 N/m2 at a temperature of 0°C. The cylinder is heated further till the thermometer records 150°C. What is the pressure of the gas?
ANSWER
P1VI/T1 =P2V2/T2
Volume remains constant therefore
P1/T1 =P2/T2
P1 =1.0× 105 N/M2
T1 = 0℃ = 0 + 273 =273K
P2 =?
T2 = 150 + 273 = 423K
1.0× 105 N/M2 ÷ 273K = P2 ÷ 423K
P2 = (1.0× 105 N/M2 × 423K) ÷ 273K
=154945.0549 N/M2
= 1.5×105 N/M2
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