Question

What weight of barium hydroxide is
present in 35.0 ml of 0.200N barium
hydroxide?

Answer 1

mass of Ba(OH)2 present in 35.0 ml of 0.200M barium

$Mass= molarity×RMM$

Mass=0.002×171.34=0.343g

$Weight=mass × g$

Weight=0.343×10

Weight=3.43N