Answer to Question #134919 in General Chemistry for Nielle

Question

2. Compute for the pOH of 0.001 M

Answer 1

Given concentration = 0.001 M

So, Concentration of OH-, [OH-]= 0.001M

So,. [OH]= 1×10^-3 M

again, pOH = -log [OH-]

= -log 10^-3

= 3

Hence, pOH of the solution = 3.

Hence, pOH of the solution = 3