Answer to Question #134919 in General Chemistry for Nielle

Question #134919
2. Compute for the pOH of 0.001 M
1
Expert's answer
2020-09-29T06:17:43-0400

Given concentration = 0.001 M


So, Concentration of OH-, [OH-]= 0.001M


So,. [OH]= 1×10^-3 M


again, pOH = -log [OH-]


= -log 10^-3


= 3

Hence, pOH of the solution = 3.


Hence, pOH of the solution = 3

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