Answer to Question #134827 in General Chemistry for Hugh

Question #134827

4. Build a voltaic cell with one beaker containing potassium permanganate (KMnO4) solution with a platinum electrode and a second beaker containing zinc chloride with a zinc electrode. Determine:

a. The half reactions

b. Flow of electrons

c. Short-form notation

d. Electric potential (voltage)

Expert's answer

a. Zn+2Cl^-=ZnCl₂+2e^-

Pt(MnO4)₂+2e^-=Pt²⁺+2MnO4^-

b. Zn= Zn²⁺ + 2e^-

Pt= Pt²⁺ + 2e^-

Zn + Pt ²⁺→ Pt+ Zn²⁺

Zn(s) ZnCl₂(s) Cl- (aq) Pt(MnO₄)₂(s) Pt(MnO₄₎(s) Pt(s)

d. ϕ(Zn)=-0.763 B

ϕ(Pt)=+1.19 B

0.763+1.19=1.953 B

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Assignment Expert

24.09.20, 21:02

Dear Hugh, Questions in this section are answered for free. We can't fulfill them all and there is no guarantee of answering certain question but we are doing our best. And if answer is published it means it was attentively checked by experts. You can try it yourself by publishing your question. Although if you have serious assignment that requires large amount of work and hence cannot be done for free you can submit it as assignment and our experts will surely assist you.

Hugh

24.09.20, 15:23

How is this possible? Isn’t Pt an inert electrode and would not be consumed in the process?

Answer to Question #134827 in General Chemistry for Hugh

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