At STP, 1 mole of any gas occupies the volume of 22.4 L. Therefore,
V(SF6)=22.4LmolV(SF_6)=22.4\frac{L}{mol}V(SF6)=22.4molL×0.235mol=5.26L\times0.235 mol= 5.26L×0.235mol=5.26L
Answer: 5.26 L
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