The analysis of a compound gives the following percent composition by mass:
C: 54.30 percent; H: 9.495 percent; S: 12.08 percent; O: 24.12 percent. What is its molecular formula given that its molar mass is 265.4 g?
C: H: S: O = 54.30/12 : 9.495/1 : 12.08/32 : 24.12/16
          = 4.525 : 9.495 : 0.3775 : 1.5075
          = 12 : 25 : 1 : 4
The empirical formula of the compound is C12H25SO4
According to question
(C12H25SO4)n = 265.4
(12×12+1×25+32×1+16×4)n =265.4
265n = 265.4
n = 1(approx)
Formula of the compound is C12H25SO4 (Answer)
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