Answer to Question #134125 in General Chemistry for Nielle

Question

Given this unbalanced reaction, how many grams of Boric acid (H3BO3) will you have if you react 25.0 grams of diboron hexahydride with excess water? Follow Significant Figures

B2H6 + H2O -> H3BO3 + H2

Answer 1

The balanced reaction is as following:

B₂H₆ + 6H₂O -> 2H₃BO₃ + 6H₂

The mass of boric acid produced can be calculated as:

m(H₃BO₃) = m(B₂H₆) × 2 × Mr(H₃BO₃) / Mr(B₂H₆).

As Mr(B₂H₆) = 27.66 g/mol and Mr(H₃BO₃) = 61.83 g/mol:

m(H₃BO₃) = 25.0 g × 2 × 61.83 g/mol / 27.66 g/mol = 111.8 g

Answer: 111.8 g