Answer to Question #134039 in General Chemistry for Dorsa

General Chemistry

Question #134039

What is the percent composition of carbon by mass in creatine, C4H9N3O2?

Expert's answer

M (C₄H₉N₃O₂) = 131.13 g/mol

%C = (4A_r(C) / M(C₄H₉N₃O₂)) * 100% = (48.04 / 131.13) * 100% = 36.64 %

Answer: 36.64 %

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