Answer to Question #134029 in General Chemistry for Kath

Question

When copper is heated with an excess of sulfur, copper(I) sulfide is formed. In a given experiment, 1.50 g of copper was heated with excess sulfur to yield 1.75 g copper(I) sulfide. What is the percent yield?

Answer 1

The equation of the given reaction is

2Cu + S --> Cu₂S

M(Cu) = 63.55 g/mol

M (Cu₂S) = 159.16 g/mol

According to the equation, 1 mole of Cu₂S can be produced from 2 moles of Cu.

Therefore, the theoretical yield is:

((1.50g / 63.55g/mol) * 159.16g/mol) / 2 = 1.88 g

% yield = (1.75g / 1.88g) * 100% = 93.1%

Answer: 93.1%