Answer to Question #133961 in General Chemistry for cj

Question

1. The neutralization reaction between HCl and Ca(OH)2 produces CaCl2 and water. If 0.75g of Ca(OH)2 is used in the reaction, determine the following:
a) Number of moles of HCl needed to completely react with Ca(OH)2¬
b) Mass of CaCl2 formed in the reaction.

Answer 1

Solution.

$m(Ca(OH)_2)=0.75g;$

$2HCl+Ca(OH)_2 \to CaCl_2+2H_2O;$

$a) M(Ca(OH)_2)=74g/mol;$

$\nu=\dfrac{m}{M}; \nu(Ca(OH)_2)=\dfrac{0.75g}{74g/mol}=0.01mol;$

$x mol$ $0.01mol$

$2HCl+Ca(OH)_2 \to CaCl_2+2H_2O;$

$2$ $1$

$x=\dfrac{2\sdot 0.01mol}{1}=0.02mol;$

$\nu(HCl)=0.02mol;$

$b) M(CaCl_2)=111g/mol;$

$0.75g$ $xg$

$2HCl+Ca(OH)_2 \to CaCl_2+2H_2O;$

$74g/mol$ $111g/mol$

$x= \dfrac{0.75g\sdot111g/mol}{74g/mol}=1.125g;$

$m(CaCl_2)=1.125g;$

Answer: $a) \nu(HCl)=0.02mol;$

$b)m(CaCl_2)=1.125g.$