Formular for sucrose"=C_{{_1}{_2}}H_{{_2}{_2}}O_{{_1}{_1}}"
The molar mass of sucrose "= 342.3g\/mol"
From the formula, "1" mole of Sucrose"=" "12" moles of Carbon.
"1" mole of Sucrose represents "6.022\\times 10^{23}" Atoms of Sucrose(Avogadro number)
"\\therefore" If "1" mole of Sucrose"= 12" moles of Carbon.
Then "0.15" moles of Sucrose
"=" "0.15 Moles \\times 12 Moles \\over 1 Mole"
"=1.8 mol C"
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