Vang=500ml
And the concetration of NaCl =0.9%
So, v(NaCl) = 500ml × 0.9/100 = 4.5ml
• Number of moles of NaCl will be
n= v/Vm = (4.5/1000)/22.4 = 0.0002mol
NaCl ----- Na+ + Cl-
So in 500 ml of solution there are 0.0002mol Na+ and 0.0002 mol Cl-
So for 5 days if will be 5 times more
n(Na+) =n(Cl-) = 0.001mol
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