M1V1= M2V2
So V2=M1V1M2\frac{M_1 V_1} {M_2}M2M1V1
V2= 3.0×0.15÷2.033.0 \times 0.15 \div 2.033.0×0.15÷2.03
which is equal to 0.221 L
so dilute the solution upto 221 mL.
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