Molar mass of "H_2O_2= 34 \\ g"
Moles of "H_2O_2= \\frac{4}{34}"
"2H_2O_2\\to 2H_2O + O_2"
So ,moles of oxygen produced will be half of hydrogen peroxide .
"n= \\frac{2}{34}"
"T=500K,V= 250\\ ml = 0.25 \\ L"
Using ideal gas equation,
"PV= nRT"
"P\\times 0.25= \\frac{2}{34}\\times 0.0821 \\times 500\\implies"
"P=9.66 \\ atm"
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