Using the values for the heat of fusion, specific heat of water, and/or heat of vaporization, calculate the amount of heat energy in each of the following.
calories need to melt 65.0 g of ice at 0 ∘C and to warm the liquid to 65 ∘C
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Expert's answer
2020-09-15T13:51:55-0400
Amount of heat energy = mL +mc"\\Delta"T ="65\\times80+65\\times1\\times65=5200+4225=9425 \\ cal"
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