At first chemical reaction should be written and balanced:
2C8H18 + 25O2 = 16CO2 + 18H2O.
The molar masses of reactants should be found:
M(O2)=2×16=32(g/mol),
M(C8H18)=8×12+18×1=114(g/mol).
Taking into account the reaction coefficients the mass of octane is found from a proportion:
x=2.3×2×114/25×32=0.6555(g).
Answer: 0.6555 g of octane.
Comments
Leave a comment