Distance to be covered (s)=35.3 m(s)= 35.3\ m(s)=35.3 m
Velocity of car (v)=30.5 m/s(v)= 30.5\ m/s(v)=30.5 m/s
Time required =sv=35.330.5=1.157 s≈1.16 s= \frac{s}{v}=\frac{35.3}{30.5}=1.157\ s\approx 1.16\ s=vs=30.535.3=1.157 s≈1.16 s ≈1.2 s\approx 1.2\ s≈1.2 s
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