You deserve 25 g of calcium carbonate and 250 mL of water what is the calcium carbonate concentration of the resulting solution
(C=12amu, O= 16amu, Ca=40amu)
1
Expert's answer
2020-09-07T08:20:36-0400
M(CaCO3) = 40 + 12 + (16*3) = 100 g/mol
25 g of CaCO3 correspond to 0.25 mol
We have 0.25 mol of CaCO3 in 250 mL or 1.0 mol in 1.0 L (1 M).
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