Question

You deserve 25 g of calcium carbonate and 250 mL of water what is the calcium carbonate concentration of the resulting solution
(C=12amu, O= 16amu, Ca=40amu)

Answer 1

M(CaCO₃) = 40 + 12 + (16*3) = 100 g/mol

25 g of CaCO₃ correspond to 0.25 mol

We have 0.25 mol of CaCO₃ in 250 mL or 1.0 mol in 1.0 L (1 M).

Answer: 1 M