Question

Assuming that Coca Cola has the same specific heat as water ( 4.18 J/(g x degrees C) ), calculate the amount of heat in J transferred when one can ( about 250g) is cooled from 15 degrees C to 6 degrees C . *

Answer 1

$∆H = mC∆T$

$m = 250 g$

$C = 4.18 \frac{J}{(g\times°C)}$

$∆T = 15 - 6 = 9 °C$

$∆H = 250 g \times 4.18 \frac{J}{(g\times°C)} \times 9 °C = 9405 J$

Answer: 9405 J