"2SO_2+O_2+2H_2O\\to 2H_2SO_4"
Given excess of "O_2" and "H_2O" ,
"2" moles of "SO_2" gives "2" moles of "H_2SO_4" .
Hence,number of moles of "H_2SO_4" produced is equal to number of moles of "SO_2" consumed .
Mass of "SO_2" consumed "=4.5 \\ g"
Molar mass of "SO_2=64\\ g"
Molar mass of "H_2SO_4=98\\ g"
Moles of"\\ SO_2" consumed "=\\frac{4.5}{64}=" Moles of "H_2SO_4" produced.
Mass of "H_2SO_4" produced "=\\frac{4.5}{64}\\times 98=6.89\\ g"
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