We know all required information for calculation the number of molecules:
"m(Cu(OH)_2)=23.45~g"
"MM(Cu(OH)_2)=97.562~g\/mol"
"Na=6.022\u00d710^{23}~mol^{-1}"
First we must find the number of moles:
"n=\\frac{m(CuOH)_2}{MM(Cu(OH)_2}=\\frac{23.45}{97.562}=0.240~mol"
Now we can calculate the number of molecules in 0.240 mol by the formula:
"N=n\u00d7Na=0.240\u00d76.022\u00d710^{23}=1.445\u00d710^{23}"
So, the answer is "1.445\u00d710^{23}"
Comments
Leave a comment