Answer to Question #130788 in General Chemistry for Nicole Xie

Question

What amount of magnesium nitride is required to react completely with 0.25 mol of water? What amounts of the products are expected?

Answer 1

Mg₃N₂ + 6H₂O --> 3Mg(OH)₂ + 2NH₃

According to the equation, the amounts in moles are:

n (Mg₃N₂) = 0.25 * 1/6 = 0.042 mol

n (Mg(OH)₂) = 0.25 * 3/6 = 0.13 mol

n (NH₃) = 0.25 * 2/6 = 0.083 mol

The masses are:

m (Mg₃N₂) = 0.25 * 1/6 * 100.95 = 4.2 g

m (Mg(OH)₂) = 0.25 * 3/6 * 58.32 = 7.3 g

m (NH₃) = 0.25 * 2/6 * 17.03 = 1.4 g