NaOH + HNO"_{3}" "\\to" NaNO"_{3}" + H2O
step 1: find the moles of reactants in terms of molarity and volume
n(NaOH) = 0.0294 moles
n(HNO"_{3}") = 0.03675 moles
step 2: determine the limiting reactant
given reaction is equal so we should just compare the moles of reactants to each other.
NaOH + HNO"_{3}" "\\to" NaNO"_{3}" + H2O
0.0294 < 0.03675
So moles of sodium hydroxide are smaller than nitric acid. Therefore, limiting reactant in this reaction is sodium hydroxide
limiting reactant "\\to" NaOH
moles of limiting reactant "\\to" 0.0294 moles
Comments
Leave a comment