At first, we should find molar mass of axinite:
M(HCa3Al2BSi4O16)=1+3×40+2×27+11+4×28+16×16=1+120+54+11+112+256=554 (g/mol).
%Al=54/554×100%=9.75%.
So, from 1 kg (or 1000 g) of axinite we obtain 97.5 g of Al.
From a proportion we calculate how much we will get for them:
x=50×97.5/1000=4.875 $.
So, for 1 kg of axinite we pay 9$ and get only 4.875$ from it. It's obvious that this proposition is not good to get rich, because we spend more than we get.
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