Let us find the actual mass of the sodium atom:
"m_{0}(Na)=22.99u*1.661*10^{-24}g\/u=3.819*10^{-23}g;"
This as a single atom, while 1 mole contains of Avogadro number of atoms:
"M_{1mol}(Na)=m_{0}(Na)*N_{A}=3.819*10^{-23}g*6.02*10^{23}=22.99g;"
Thus, the mole of sodium atoms weights 22.99 grams.
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