A solution is prepared from 20mL of 0.10M HNO3 and 30mL of 0.05M H2SO4. If the H2SO4 completely ionises, the pH of the solution would be:
A. +1 B. +3 C. –log 0.02 D. –log 0.07
n1(H+)=c(HNO3)V1=0.10M∗0.02L=0.002mol
n2(H+)=2c(H2SO4)V2=2∗0.05M∗0.03L=0.003mol
ntotal=0.002mol+0.003mol=0.005mol
Vtotal=0.02L+0.03L=0.05L
c(H+)=n/V=0.005mol/0.05L=0.10M
pH=−logc(H+)=+1 Answer: A +1