Answer to Question #128769 in General Chemistry for Jocabed Jimenez

Question

If a 0.025 M solution of a weak acid, HA, is 4.2% ionized, what is the Ka value for the weak acid?

Saccharin, HNC7H4SO3, a sugar substitute is a weak monoprotic acid with a pKa = 4.32 What is the pH of a 0.12 M solution of this substance?

Carbonic acid, H2CO3 is present in carbonated or carbonated beverages. Calculate the pH and concentration of the carbonate ion (CO32-) of a 0.025 M solution of carbonic acid. Ka1 = 4.3 x 10-7; Ka2 = 5.6 x 10-11

Answer 1

Ka= 0.042 x 0.042 x 0.025 = 4,41e-5