Answer to Question #127974 in General Chemistry for jonnathan alexander salas

Question

Product A is added into a solution at a dosage of 70 mg/L. The
product contains molybdate. An analysis shows that the solution now
contains 5 mg/L of molybdate. What was the % molybdate in product A?

Answer 1

Given values suggest that out of 70 mg of the product A there are 5 mg of molybdate.

Therefore, % molybdate = (5mg / 70mg) x 100% = 7.14 %

Answer: 7.14 %