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Answer to Question #127974 in General Chemistry for jonnathan alexander salas

Question #127974
Product A is added into a solution at a dosage of 70 mg/L. The
product contains molybdate. An analysis shows that the solution now
contains 5 mg/L of molybdate. What was the % molybdate in product A?
1
Expert's answer
2020-08-02T15:51:16-0400

Given values suggest that out of 70 mg of the product A there are 5 mg of molybdate.

Therefore, % molybdate = (5mg / 70mg) x 100% = 7.14 %

Answer: 7.14 %


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